Cipher Puzzle - Solution
The Puzzle:
Find the code!
• It has 6 different digits
• Even and odd digits alternate (note: zero is an even number)
• Digits next to each other have a difference greater than one
• When we break the code into three sets of two-digit numbers, then the first and middle are a multiple of the last
What is the code? (more than 1 solution)
Our Solution:
With even and odd digits alternating, and difference greater than one, then the last 2 digits can only be:
03, 05, 07, 09, 14, 16, 18, 25, 27, 29, 30, 36, 38, 41, 47, 49, ... any higher and we can't make multiples for the first or second pair
Let's check for multiples where even and odd digits alternate and have difference greater than one:
03 has 27, 63, 69, 81
07 has 49, 63
09 has 27, 63, 81
18 has 36, 72, 90
25 has none
27 has none ...
No others work following the rules
When we try to make full numbers that follow all the rules we find only these:
692703
816903
496307
816309
903618