Zero Product Property

Zero Product Property

The "Zero Product Property" says that:

If   a × b = 0   then   a = 0   or   b = 0  
(or both a=0 and b=0)

It can help us solve equations:

Example: Solve (x−5)(x−3) = 0

The "Zero Product Property" says:

If  (x−5)(x−3) = 0  then   (x−5) = 0   or   (x−3) = 0

Now we just solve each of those:

For (x−5) = 0 we get x = 5

For (x−3) = 0 we get x = 3

And the solutions are:

x = 5, or x = 3

Here it is on a graph:

Graph of (x-5)(x-3) = 0 showing intersections at x=3 and x=5
y=0 when x=3 or x=5

Standard Form of an Equation

Sometimes we can solve an equation by putting it into Standard Form and then using the Zero Product Property:

The "Standard Form" of an equation is:

(some expression) = 0

In other words, "= 0" is on the right, and everything else is on the left.

Example: Put x2 = 7 into Standard Form

Answer:

x2 − 7 = 0

This works because with the equation equal to 0 we can identify its factors. If the product of the factors is 0, then one or more of those factors must be 0.

Standard Form and the Zero Product Property

So let's try it out:

Example: Solve 5(x+3) = 5x(x+3)

We might be tempted to divide by (x+3), but this would mean dividing by zero when x = −3

So instead we can use "Standard Form":

5(x+3) − 5x(x+3) = 0

Which can be simplified to:

(5−5x)(x+3) = 0

5(1−x)(x+3) = 0

Then the "Zero Product Property" says:

(1−x) = 0, or (x+3) = 0

And the solutions are:

x = 1, or x = −3

And another example:

Example: Solve x3 = 25x

It is tempting to divide by x, but that is dividing by zero when x = 0

So let's use Standard Form and the Zero Product Property.

 

Bring all to the left hand side:

x3 − 25x = 0

Factor out x:

x(x2 − 25) = 0

x2 − 25 is a difference of squares, and can be factored into (x − 5)(x + 5):

x(x − 5)(x + 5) = 0

Now we can see three possible ways it could end up as zero:

x = 0, or x = 5, or x = −5

Summary of Steps

 

509, 510, 1140, 4030, 1141, 4031, 2292, 4032, 2293, 4033